Treść zadania
Autor: maaajaaa Dodano: 20.5.2010 (20:52)
do 0,5kg4-procentowego roztworu soli dosypano 20g tej soli.Oblicz stężenie procentowe otrzymanego roztworu.
Komentarze do zadania
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Paskuuda 20.5.2010 (21:09)
początkowy roztwór: cp (stężenie %) = 4% masa roztworu = 0,5 kg (500g)
100 % - 500g
4% - x
x= 20g
masa substancji rozpuszczonej = 20 g
masa rozpuszczalnika = 500 - 20 = 480g
nowy roztwor: masa substancji = 20 + 20g = 40g
masa rozwtworu = 480g (masa rozpuszczalnika) + 40 g = 520g
520 g = 100%
40g = x
x= 7,7%
Cp = 7,7 % -
maaajaaa 20.5.2010 (20:55)
jak moglbyscie to zróbcie mi to zad. z jakimiś cp ms tez jest ! tak musze mieć
Zadanie jest zamknięte. Autor zadania wybrał już najlepsze rozwiązanie lub straciło ono ważność.
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Rozwiązania
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lllidiaaa123 20.5.2010 (20:53)
4% x 0,5 kg = 0,02kgsoli
0,02kg = 20g
20g+20g = 40gsoli
40 / 500g soli + 20g soli = 7,7%Dodawanie komentarzy zablokowane - Zgłoś nadużycie
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Konto usunięte 21.5.2010 (10:27)
Cp = ms*100%/mr
mr = 0,5kg = 500g
4% = ms*100%/500
4%*500 = ms*100%
ms1 = 20g
ms2 = 20g+20g = 40g
mr2 = 500g+20g = 520g
Cp2 = 40*100%/520
Cp2 = 7,69%
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