Treść zadania
Autor: papaya Dodano: 2.2.2012 (10:49)
[3*(1/2)^3 - 2/3 :(2/3)^2 ]^2=
(1/3)^2 + (1/3)^3 * 2/3 - 2/3 : (1/2)^3 =
3*[2/3:(2/4 - 3/4: 3/16 + 5/8 : 25/48) - 4/5]^2 =
6/7* (1/2)^2 + [3/7 :(1/3)^3 - 3/4 : 5/16]^2=
(1/7)^2 - 2/3 :(3/4)^2 + 2/3* (1/2)^2=
Zadanie jest zamknięte. Autor zadania wybrał już najlepsze rozwiązanie lub straciło ono ważność.
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aniam 2.2.2012 (11:52)
[3*(1/2)^3 - 2/3 :(2/3)^2 ]^2=[3*1/8-2/3:4/9]^2=[3/8-2/3*9/4]^2=[3/8-3/2]^2=[3/8-1 1/2]^2=[3/8-1 4/8]^2=(1 1/8)^2=(9/8)^2=81/64=1 17/64
(1/3)^2 + (1/3)^3 * 2/3 - 2/3 : (1/2)^3 = 1/9+1/27*2/3-2/3:1/8=1/9+2/81-2/3*8=9/81+2/81-16/3=11/81-5 1/3=11/81-5 27/81=-5 16/81Dodawanie komentarzy zablokowane - Zgłoś nadużycie
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sonar 6.2.2012 (21:27)
[3*(1/2)^3 - 2/3 :(2/3)^2 ]^2=
= [ 3 * 1/8 – 2/3 : 4/9]^2=
= [3/8 – 2/3 * 9/4]^2 = (skracam 2 z 4 oraz 3 z9)
=[3/8 – 1/1* 3/2]^2=
= [3/8 – 3/2]^2=
= [3/8 – 12/8]^2=
= [- 9/8]^2=
= 81/64=
= 1 i 17/64
(1/3)^2 + (1/3)^3 * 2/3 - 2/3 : (1/2)^3 =
= 1/9 + 1/27 * 2/3 – 2/3 : 1/8=
= 1/9 + 2/81 – 2/3 * 8/1=
= 9/81 + 2/81 – 16/3=
= 11/81 – 5 i 1/3=
= 11/81 – 5 i 27/81=
= - 5 i 16/81
3*[2/3:(2/4 - 3/4: 3/16 + 5/8 : 25/48) - 4/5]^2 =
= 3* [2/3 : ( 2/4 – ¾ * 16/3 + 5/8 * 48/25]^2=
= 3* [ 2/3 : ( 2/4 – 1/1 * 4/1 + 1/1 * 6/1]^2=
= 3 * [ 2/3 : ( 2/4 – 4/1 + 6/1] ^2=
= 3 * [ 2/3 :( -3 i 2/4 + 6]^2=
= 3* [2/3 : 2 i 2/4]^2=
= 3* [ 2/3 : 10/4]^2=
= 3 * [ 2/3 * 14/10]^2=
= 3* [ 1/3* 14/5]^2=
= 3* [14/15]^2=
=3 * 196/225=
= 588/225=
= 2 i 138/225=
= 2 i 46/75
6/7* (1/2)^2 + [3/7 :(1/3)^3 - 3/4 : 5/16]^2=
= 6/7 * ¼ + [ 3/7 : 1/27 – ¾ * 16/5]^2=
= 3/7 * ½ + [ 3/7 * 27/1 – 3/1 * 4/5]^2=
= 3/14 + [ 81/7 – 12/5]^2=
= 3/14 + [ 405/35 – 84/35]^2=
= 3/14 + [ 321/35]^2=
= 3/14 + 103041/1225=
= 3675/17150 + 721287/17150=
= 724962/17150=
= 42 i 4662/17150
(1/7)^2 - 2/3 :(3/4)^2 + 2/3* (1/2)^2=
= 1/49 – 2/3 : 9/16 + 2/3 * ¼=
= 1/49 – 2/3 * 16/9 + 1/3 * 1/1=
= 1/49 – 32/27 + 1/3=
= 27/1323 – 1568/1323 + 441/1323=
= - 1120/1323
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