Treść zadania

Najlepsze rozwiązanie

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  ewka13 19.9.2011 (18:12)

  a)
  \frac {6} {7}\cdot \frac {5} {8} =skracamy \ przez \ 2 =\frac {15} {28}
  
  b)
  \frac {2} {8}\cdot \frac {5} {9} = \frac {10} {72}
  
  c)
  \frac {4} {19}\cdot 2\frac {3} {8} = \frac {4} {19} \cdot \frac {19} {8}=skracamy \ przez \ 19 \ i \ 4=\frac {1} {2}
  
  w nawiasie [ ] bedzie przez co skrócić
  d)
  3\frac {3} {8}\cdot \frac {8} {9} = \frac {27} {8} \cdot \frac {8} {9}=[8 , 9]=3
  
  e)
  \frac {7} {11}\cdot \frac {12} {24}= \frac {7} {11}\cdot \frac {1} {2} =\frac {7} {22}
  
  f)
  1\frac {1} {2} \cdot \frac {2} {3}= \frac {3} {2}\cdot \frac {2} {3} =1
  
  g)
  3\frac {1} {5}\cdot 2\frac {1} {4} =\frac {16} {5}\cdot \frac {9} {4}=[4]=\frac {36} {5}=7\frac {1} {5}
  
  h)
  \frac {1} {9}\cdot 9\frac {1} {2} = \frac {1} {9}\cdot \frac {19} {2}=\frac {19} {18} =1\frac {1} {18}
  
  i)
  \frac {3} {7} : \frac {7} {3} =\frac {3} {7}\cdot \frac {3} {7} = \frac {9} {49}
  
  j)
  4\frac {1} {5} : \frac {7} {10} =\frac {21} {5} \cdot \frac {10} {7} =[5 , 7]=6
  
  k)
  \frac {1} {2} : 1\frac {1} {4} =\frac {1} {2}\cdot \frac {4} {5} =[2] = \frac {2} {5}
  
  l)
  1\frac {1} {8} : 8 = \frac {9} {8} \cdot \frac {1} {8} = \frac {9} {64}
  
  m)
  \frac {4} {8} : \frac {1} {2} = \frac {1} {2} \cdot \frac {2} {1} =1
  
  n)
  3\frac {3} {11} : 3=\frac {36} {11}\cdot \frac {1} {3} =[3]=\frac {12} {11} = 1\frac {1} {11}
  
  o)
  2\frac {3} {7} : 4\frac {6} {7} =\frac {17} {7} \cdot \frac {7} {34}=[7,17] = \frac {1} {2}.

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