Treść zadania

kamilkaa12342

Ułamki zwykłe: DAM NAJJJJJJ !!!!!

a) 3\8+5/6-7/12=
b) 2 1/6-1 1/2 + 1/8=
c) 5 1/14 - 2 1/4 - 1 3/3=

i ) 1 1/5 x 1 2/3 x 1/7 + (1 1/7)2=
j ) (2 1/6 - 2/3)2 - 2 1/5=
k)10-2 x (3 1/5 - 2 1/4 x 1/3) =
l) (7/3 - 5/12 + 1 1/2 ) : ((2 3/4 - 5/6)=



(....)2 czyli do potęgi drugiej
a np: 2 13/5 czy dwie całe i trzynaście piątych ...

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Komentarze do zadania

  • dzięki david za poprawkę, faktycznie tak powinno być jak napisałeś w j)

Zadanie jest zamknięte. Autor zadania wybrał już najlepsze rozwiązanie lub straciło ono ważność.

Najlepsze rozwiązanie

  • 3 0

    a) \ \frac { 3}{8}+ \frac { 5}{6}- \frac { 7}{12}= \frac {3 \cdot 3+4 \cdot 5-7 \cdot 2}{24}= \frac {15}{24}= \frac {5}{8}

    b) \ 2 \frac {1}{6}-1 \frac {1}{2} + \frac {1}{8}=2 \frac {4}{24}-1 \frac {12}{24}+ \frac {3}{24}= \frac {16}{24}+ \frac {3}{24}= \frac {19}{24}

    c) \ 5 \frac {1}{14} - 2 \frac {1}{4} - 1 \frac {3}{7}= 5 \frac {2}{28}-2 \frac {7}{28}-1 \frac {12}{28}=2 \frac {23}{28}-1 \frac {12}{28}= 1\frac {11}{28}


    i ) \ 1 \frac {1}{5} \cdot 1 \frac {2}{3} \cdot \frac {1}{7} + \left(1 \frac {1}{7}\right)^2= \frac {6}{5} \cdot \frac {5}{3} \cdot \frac {1}{7}+\left( \frac {8}{7}\right)^2= \frac {2}{7}+ \frac {64}{49}= \frac {14}{49}+ \frac {64}{49}= \frac {78}{49}=1 \frac {29}{49}


    j ) \ \left (2 \frac {1}{6} - \frac {2}{3}\right)^2 - 2 \frac {1}{5}=\left (2 \frac {1}{6} - \frac {4}{6}\right)^2 - 2\frac {1 }{5}=\left ( \frac {7}{6}\right)^2 - 2 \frac {1}{5}= \frac {49}{36}- 2 \frac {1}{5}=1 \frac {13}{36}-2 \frac {1}{5}=

    =1 \frac {65}{180}-2 \frac {36}{180}= -\frac {151}{180}



    k) \ 10-2 \cdot \left(3 \frac {1}{5} - 2 \frac {1}{4} \cdot \frac {1}{3} \right) =10-2\left(3,2- \frac {9}{4} \cdot \frac {1}{3}\right)=

    =10-2(3,2-0,75)=10-2 \cdot 2,45=10-4,9=5,1


    l) \ \left( \frac {7}{3} - \frac {5}{12} + 1 \frac {1}{2} \right) : \left( 2 \frac {3}{4} - \frac {5}{6}\right)=\left( 2\frac {4}{12} - \frac {5}{12} + 1 \frac {6}{12} \right) : \left( 2 \frac {9}{12} - \frac {10}{12}\right)=

    =\left( 1\frac {1}{12}+ 1 \frac {6}{12} \right) : \left(1 \frac {11}{12} \right)=\left( 2\frac {17}{12} \right) : \left( \frac {23}{12} \right)= \frac {41}{12} \cdot \frac {12}{23}= \frac {41}{23}=1 \frac {18}{23}

Rozwiązania

  • userphoto

    a)\frac{3}{8} + \frac{5}{6} - \frac{7}{12} = \frac{9}{24} + \frac{20}{24} - \frac{14}{24} = \frac{29}{24} - \frac{14}{24} = \frac{15}{24} = \frac{5}{8}

  • userphoto

    j) (2 1/6 - 2/3)2 - 2 1/5=(13/6-4/6)2 - 2 1/5=(9/6)2 - 2 1/5 = 81/36 - 11/5= 9/4 - 11/5= 45/20 - 44/20= 1/20

  • userphoto

    a) 3/8 +5/8 - 7/12 = 18/48 + 40/48 - 28/48 = 58/48-28/48 = 30/48 = 5/8
    b) 2 1/6 - 1 1/2 + 1/8 = 13/6 - 3/2 + 1/8 = 52/24 - 36/24 + 3/24 = 19/24
    c) 5 1/14 - 2 1/4 - 1 3/3= 71/14 - 9/4 - 6/3 = 426/84 - 189/84 - 168/84 = 69/84 = 23/28
    i) 1 1/5 x 1 2/3 x 1/7 + (1 1/7)2= 6/5 x 5/3 x1/7 + (8/7)2 = 2/7 + 64/49 = 14/49 +64/49= 78/49 = 1 29/49
    j) (2 1/6 - 2/3)2 - 2 1/5= (3/6 - 2/3)2 - 11/5 = (13/6 - 4/6)2 - 11/5 = (9/6)2 - 11/5 = 81/36 -11/5 = 405/180 - 396/180 = 9/180 = 1/20
    k)10-2 x (3 1/5 - 2 1/4 x 1/3) = 10 - 2 x (16/5 - 9/4 x 1/3) = 10 x 2 x (16/5 - 3/4) = 10 - 2 x (64/20 - 15/20) = 10 - (2 x 49/20) = 10 - 49/20 = 9 20/20 - 49/20 - 200/20 - 49/20 = 151/20 = 7 11/20
    l) (7/3 - 5/12 + 1 1/2 ) : (2 3/4 - 5/6)= (7/3 - 5/12 + 3/2) : (11/4 - 5/6) = (28/12 - 5/12 + 18/12) : (33/12 - 10/12) = 41/12 : 23/12 = 41/12 x 12/23 = 41/23 = 1 18/23

  • userphoto

    a) 3/8+5/6-7/12=9/24+20/24-14/24=15/24=5/8

  • sonar

    a)
    3/8 + 5/6 - 7/12=

    = 9/24 + 20/24 - 14/24=

    = 29/24 - 14/24=

    = 15/24=

    = 5/8


    b)
    2 i 1/6 - 1 i 1/2 + 1/8=

    = 2 i 4/24 - 1 i 12/24+ 3/24=

    = 1 i 28/24 - 1 i 12/24 + 3/24=

    = 16/24 + 3/24 =

    = 19/24


    c) Czy w tym przykładzie nie ma przypadkiem pomyłki ? Chodzi mi o 1 i 3/3 . Zrobię kilka wersji tego działania.
    1.
    5 i 1/14 - 2 i 1/4 - 1 i 3/3=

    = 5 i 2/28 - 2 i 7/28 - 2=

    = 4 i 30/28 - 2 i 7/28 -2=

    = 2 i 23/28 - 2=

    = 23/28

    2. Zamiast 1 i 3/3 wstawię 1 i 3/6

    5 i 1/14 - 2 i 1/4 - 1 i 3/6=

    = 5 i 6/84 - 2 i 21/84 - 1 i 42/84=

    = 4 i 90/84 - 2 i 21/84 - 1 i 42/84=

    = 2 i 69/84 - 1 i 42/84=

    = 1 i 27/84=

    =1 i 9/28


    3) za 1 i 3/3 podstawię 1 i 3/7

    5 i 1/14 - 2 i 1/4 - 1 i 3/7 =

    = 5 i 2/28 - 2 i 7/28 - 1 i 12/28 =

    = 4 i 30/28 - 2 i 7/28 - 1 i 12/28=

    = 2 i 23/28 - 1 i 12/28=

    = 1 i 11/28


    4) za 1 i 3/3 podstawię 1 i 3/8

    5 i 1/14 - 2 i 1/4 - 1 i 3/8=

    = 5 i 4/56 - 2 i 14/56 - 1 i 21/28=

    = 4 i 60/56 - 2 i 14/56 - 1 i 21/28=

    = 2 i 46/56 - 1 i 21/56=

    = 1 i 25/56


    i )
    1 i 1/5 * 1 i 2/3 * 1/7 + (1 i1/7)^2=

    = 6/5 * 5/3 * 1/7 + ( 8/7)^2=

    =6/1 * 1/3 * 1/7 + 64/49 =

    = 6/21 + 1 i 15/49 =

    = 2/7 + 1 i 15/49 =

    = 14/49 + 1 i 15/49=

    = 1 i 29/49


    j )
    (2 i 1/6 - 2/3)^2 - 2 i 1/5=

    =( 2 i 1/6 - 4/6)^2 - 2 i 1/5=

    = (1 i 7/6 - 4/6)^2 - 2 i 1/5=

    = (1 i 3/6)^2 - 2 i 1/5=

    = (9/6)^2 - 2 i 1/5=

    = 81/36 - 2 i 1/5=

    = 9/4 - 2 i 1/5=

    = 2 i 1/4 - 2 i 1/5=

    = 2 i 5/20 - 2 i 4/20 =

    = 1/20



    k)
    10-2 * (3 i 1/5 - 2 i 1/4 * 1/3) =

    = 10 - 2*( 3 i 1/5 - 9/4 * 1/3)=

    = 10 - 2*( 3 i 1/5 - 3/4 * 1/1) =

    = 10 - 2* ( 3 i 1/5 - 3/4)=

    = 10 - 2* ( 3 i 4/20 - 15/20)=

    = 10 - 2 * ( 2 i 24/20 - 15/24) =

    = 10 - 2 * 2 i 9/20 =

    = 10 - 2 * 49/20 =

    = 10 - 98/20=

    = 10 - 49/10 =

    = 10 - 4 i 9/10 =

    = 5 i 1/10



    l)
    (7/3 - 5/12 + 1 i1/2 ) : (2 i 3/4 - 5/6)=

    = ( 28/12 - 5/12 + 1 i 6/12 ) : ( 2 i 9/12 - 10/12)=

    = 1 i 29/12 : 1 i 11/12 =

    = 41/12 : 23/12=

    = 41/12 * 12/23=

    = 41/1 * 1/23=

    = 41/23=

    = 1 i 18/23

  • paulisia1951986

    Proszę :****
    A) 3/8 +5/8 - 7/12 = 18/48 + 40/48 - 28/48 = 58/48-28/48 = 30/48 = 5/8

    B) 2 1/6 - 1 1/2 + 1/8 = 13/6 - 3/2 + 1/8 = 52/24 - 36/24 + 3/24 = 19/24

    C) 5 1/14 - 2 1/4 - 1 3/3= 71/14 - 9/4 - 6/3 = 426/84 - 189/84 - 168/84 = 69/84 = 23/28

    I) 1 1/5 x 1 2/3 x 1/7 + (1 1/7)2= 6/5 x 5/3 x1/7 + (8/7)2 = 2/7 + 64/49 = 14/49 +64/49= 78/49 = 1 29/49

    J) (2 1/6 - 2/3)2 - 2 1/5= (3/6 - 2/3)2 - 11/5 = (13/6 - 4/6)2 - 11/5 = (9/6)2 - 11/5 = 81/36 -11/5 = 405/180 - 396/180 = 9/180 = 1/20

    K)10-2 x (3 1/5 - 2 1/4 x 1/3) = 10 - 2 x (16/5 - 9/4 x 1/3) = 10 x 2 x (16/5 - 3/4) = 10 - 2 x (64/20 - 15/20) = 10 - (2 x 49/20) = 10 - 49/20 = 9 20/20 - 49/20 - 200/20 - 49/20 = 151/20 = 7 11/20

    L) (7/3 - 5/12 + 1 1/2 ) : (2 3/4 - 5/6)= (7/3 - 5/12 + 3/2) : (11/4 - 5/6) = (28/12 - 5/12 + 18/12) : (33/12 - 10/12) = 41/12 : 23/12 = 41/12 x 12/23 = 41/23 = 1 18/23

    Mam nadzieję że pomogłam! :>
    Mogę dostać Najjjj :* ?

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