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  ewka13 16.3.2011 (01:14)

  PbO_{2}
  
  \frac {Pb} {O} = \frac {207} {32}
  
  CrCl_{3}
  
  \frac {Cr} {Cl} = \frac {52} {106,5}=\frac {104} {213}
  
  K_{2}O
  
  \frac {K} {O} = \frac {78} {16} =\frac {39} {8}
  
  NH_{3}
  
  \frac {N} {H} = \frac {14} {3}
  
  CO_{2}
  
  \frac {C} {O} = \frac {12} {32} =\frac {3} {8}
  
  CO
  
  \frac {C} {O} =\frac {12} {16} =\frac {3} {4}
  
  SO_{2}
  
  \frac {S} {O} = \frac {32} {32} = \frac {1} {1}
  
  P_{4}O_{10}
  
  \frac {P} {O} =\frac {124} {160}=\frac {31} {40}
  
  P_{2}O_{3}
  
  \frac {P} {O} =\frac {62} {48}=\frac {31} {24}

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