Treść zadania
Autor: 15946691 Dodano: 1.12.2010 (11:37)
(2a-b)(a-7b)(5-c) =
(a-3(b-1)(c+8) =
-(a-1)(c-2)(b+3) =
z(y-2)(3x-1)(y-4)=
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ButterflyEffy 1.12.2010 (12:13)
(^2 - do potęgi 2)
(2a - b)(a - 7b)(5 -c) =
= (2a^2 - 14ab -ab + 7b^2)(5 - c) =
= 10a^2 - 70ab - 5ab + 35b^2 - 2ca^2 + 14abc + abc - 7cb^2 =
= 10a^2 - 75ab + 35b^2 - 2ca^2 + 15abc - 7cb^2
(a -3)(b-1)(c+8)=
= (ab - a - 3b +3)(c + 8) =
= abc - ac - 3bc + 3c + 8ab - 8a - 24b + 24 =
= -8a - 24b + 3c + 8ab - ac - 3bc + abc + 24
-(a-1)(c-2)(b+3) =
= (-a +1)(c-2)(b+3) =
= (-ac + 2a + c - 2)(b+3) =
= -abc + 2ab +cb - 2b - 3ac + 6a + 3c - 6
z(y-2)(3x-1)(y-4) =
= (zy - 2z)(3x-1)(y-4) =
= (3xyz - zy - 6xz + 2z)(y-4) =
= 3xzy^2 - zy^2 - 6xyz - 2yz - 12xyz + 4zy + 24xz - 8z =
= 3xzy^2 - zy^2 - 18xyz + 2zy + 24 xz - 8z
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