Treść zadania

Najlepsze rozwiązanie

• 

  0 0

  skromna 27.10.2010 (18:00)

  d to delta
  v0 to 'v zero' czyli szybkość początkowa
  3.
  DANE:
  s = 100m
  t = 10s
  v0 = 0m/s
  SZUKANE:
  a, vk
  
  s = v0*t +/ - at^2/2
  s = at^2/2
  100 = a 10^2/2
  100 = 100a/2
  100 = 50a /:50
  a = 2 m/s^2
  
  a = dV/dt
  a = vk - V0 / dt
  a = vk/ dt
  2 = vk/10 /*10
  vk = 20 m/s
  
  4. a = dv/dt
  a = v - v0/dt
  a = 4 - 0/3
  a = 4/3 m/s^2
  w 5s
  4/3 = v/5 / *5
  v = 6 i 2/3 m/s
  w 6s
  4/3 = v/6 /*6
  v = 8 m/s
  
  5. DANE:
  a = 2m/s^2
  v0 = 5m/s
  vk = 15m/s
  
  SZUKANE:
  t, s
  
  a = dv/dt
  a = vk - v0/dt
  2 = 10/dt /:10
  1/dt = 0,2
  t = 5s
  
  s = v0*t +/- at^2/2
  s = 5*5 + 2*5^2/2
  s = 25 + 50/2
  s = 50m
  
  6. rys.4a
  
  a = 30/3
  a = 10m/s^2
  
  s = 10*3/2
  s=45m
  
  s = 1/2v0*t
  s = 15*2
  s=30m
  
  s = 45 + 30 = 75m
  v=s/t
  v = 75/5
  v = 15m/s
  
  rys. 4b
  
  s = 1/2v0 * t
  s = 1/2 * 10 * 3
  s = 15m
  
  a = 20/2
  a = 10 m/s^2
  
  s = 10 * 2^2/2
  s = 20m
  
  s = 20 + 15 = 35m
  
  v = s/t
  v = 35 / 5
  v = 7m/s
  
  

  Dodawanie komentarzy zablokowane - Zgłoś nadużycie