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Autor: magdalena19920225 Dodano: 10.10.2010 (14:41)
Środek okręgu o równaniu x2+y2-6x=8y-11=0 ma współrzędne : A.... S=(-3,4) B.S=(-6,8) C.S=(3,-4) D.S=(6,-8)
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uzdolniony 10.10.2010 (20:39)
x^2-6x+y^2+8y-11=0
(x-3)^2+(y+4)^2-36=0
(x-3)^2+(y+4)^2=r^2
r=6,S=(3,-4)
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